Module 3 (M3) - Algebra - Factorising

Part of MathsM3: Algebra

Factorising quadratic expressions

Factorising an expression means finding the factors that multiply together to give that expression.

A quadratic expression is one that has an โ€˜๐“ยฒโ€™ term as its highest power.

\(\mathbf {x^2}\), \(\mathbf {2x^2 -3x}\), \(\mathbf {x^2 - 9}\) and \(\mathbf {x^2 + 5x + 6}\) are all quadratic expressions.

Some quadratic expressions cannot be factorised.

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Factorising quadratic expressions of the form \(\mathbf {x^2 + bx + c}\)

To find a method for factorising an expression such as \(\mathbf {x^2 + 5x + 6}\), look at how that expression was arrived at by expanding two brackets.

(x + 2)(x + 3) = x(x + 3) + 2(x + 3) 		= x2 + 3x + 2x + 6 		= x2 + 5x + 6

There are three terms in the expanded expression:

First term:
๐“ยฒ

Second term:
sum of +2๐“ and +3๐“

Third term:
product of +2 and +3

This information gives us a method for factorising.

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Examples

Factorise \(\mathbf {x^2 + 2x โ€“ 15}\):

To Factorise:

  • Find two numbers whose sum is +2 and whose product is โ€“15

The product is minus 15, so one of factors must be negative.

The numbers needed are either:

+5 and -3 or -5 and +3 As the sum is positive, the pair with the higher + value is the one to choose i.e.
+5 and -3

  • Write down the factors:

\(\mathbf {x^2 + 2x โ€“ 15 = (x + 5)(x โ€“ 3)}\)

  • Answer:
    \(\mathbf {x^2 + 2x โ€“ 15 = (x + 5)(x โ€“ 3)}\)
    \(\mathbf {(x - 3)(x + 5)}\) is also a correct answer. The order of the factors does not matter.
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Question

Factorise \(๐“ยฒ + 5๐“ โ€“ 24\)

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E๐“ample

Factorise ย ย ย ย ย ย ย ย ย ย ย ย ย ย ย ๐“ยฒ - 9๐“ + 20

Solution

Identify the product and sum of the two key values that we need to find.

  • Product = +20

  • Sum = - 9
    -4 and -5 add to give -9 and multiply to give +20

  • The factors are (๐“ - 4) and (๐“ - 5)

Answer: ๐“ยฒ - 9๐“ + 20 = (๐“ - 4)(๐“ - 5)

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Question

Factorise xยฒ - 17x + 70

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Factorising expressions of the form ๐“ยฒ-aยฒ (difference of two squares)

Expressions such as ๐“ยฒ-aยฒ can be factorised using the difference of two squares method.

To understand how this works, look at the result when (๐“ + 5)(๐“ โ€“ 5) is expanded.

(๐“ + 5)(๐“ โ€“ 5) = ๐“(๐“ -5) + 5(๐“ โ€“ 5) = ๐“ยฒ โ€“ 5๐“ + 5๐“ โ€“ 25 Since = ๐“ยฒโ€“ 25 Expanding (๐“ + 5)(๐“ โ€“ 5) gives ๐“ยฒ โ€“ 25

The inverse of this means that ๐“ยฒ โ€“ 25 factorises to give (๐“ + 5)(๐“ โ€“ 5)

  • Note that in the expression ๐“ยฒ โ€“ 25 ๐“ is squared
  • 25 = 5ยฒ and there is a minus sign in between so we have the difference of two squares!

In general, ๐“ยฒ โ€“ aยฒ can be factorised to give (๐“ + a)(๐“ โ€“ a)

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Both ๐“ยฒ and 100 (10ยฒ) are squares and there is a - sign in between.

Use the difference of two squares method - DOTS.

The factors can be written down without any further working.

๐“ยฒ โ€“ 100 = ๐“ยฒ โ€“ 10ยฒ

= (๐“ + 10)(๐“ โ€“ 10)

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Question

Factorise ๐“ยฒ - 49

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Example

Factorise 9 - ๐“ยฒ

DOTS can still be used here โ€“ the expression does not have to start with โ€˜๐“ยฒโ€

9 - ๐“ยฒ = 3ยฒ - ๐“ยฒ

Factors are (3 + ๐“)(3 โ€“ ๐“)

Answer:
9 - ๐“ยฒ = (3 + ๐“)(3 โ€“ ๐“)

Difference of two squares (DOTS) often appears on exams

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Test yourself

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